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In an ice skating competition, the order in which competitors skate is determined by a drawing. If there are 10 skaters in the finals, how many different orders are possible?

Respuesta :

bloomyhans

Answer:

3628800

Step-by-step explanation:

If there are 10 skaters, it would go from 9, 8, 7, and so on...

So..

10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1

= 3628800

3628800 orders are possible in which the competitor's skate is determined by drawing.

Factorial:

The product of all positive integers less than or equal to a given positive integer gives its factorial. It is denoted by the exclamatory sign at the end of the given positive integer.

Calculating the number of orders:

Here it is given that there are 10 skaters in the final.

The order in which competitors skate is determined by a drawing.

So, the number of possible orders is given by the Factorial of the number of skaters i.e.,

10! = 10×9×8×7×6×5×4×3×2×1

    = 3628800

Therefore,  3628800 different orders are possible for determining competitors' skate by a drawing.

Learn more about factorial here:

https://brainly.com/question/20853960

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