Respuesta :
Answer:
0.0862 M
Explanation:
Considering:
[tex]Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}[/tex]
Or,
[tex]Moles =Molarity \times {Volume\ of\ the\ solution}[/tex]
Given :
For [tex]HCl[/tex] :
Molarity = 0.1096 M
Volume = 50.00 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 50.00 × 10⁻³ L
Thus, moles of [tex]HCl[/tex] :
[tex]Moles=0.1096 \times {50.00\times 10^{-3}}\ moles[/tex]
Moles of [tex]HCl[/tex] = 0.00548 moles
According to the reaction,
[tex]2HCl+Ba(OH)_2\rightarrow BaCl_2+2H_2O[/tex]
2 moles of HCl react with 1 mole of [tex]Ba(OH)_2[/tex]
1 mole of HCl react with 1/2 mole of [tex]Ba(OH)_2[/tex]
0.00548 mole of HCl react with (1/2)*0.00548 mole of [tex]Ba(OH)_2[/tex]
Moles of [tex]Ba(OH)_2[/tex] = 0.00274 moles
Volume of [tex]Ba(OH)_2[/tex] = 31.78 mL = 31.78 × 10⁻³ L
Molarity = 0.00274 moles / 31.78 × 10⁻³ L = 0.0862 M
The molarity of the Ba(OH)2 solution is mathematically given as
M= 0.0862 M
What is the molarity of the Ba(OH)2 solution?
Question Parameters:
A 50.00 mL sample of constant‑boiling HCl
a concentration of 0.1096 M
31.78 mL of a Ba(OH)2 solution.
Generally, the equation for the Molarity is mathematically given as
[tex]M=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}[/tex]
Where,moles of HCl is
Hm=0.1096* {50.00* 10^{-3}} moles
Hm= 0.00548 moles
The equation for the Chemical Reaction is mathematically given as
2HCl+Ba(OH)_2 ----> BaCl_2+2H_2O
Hence
Moles of Ba(OH)_2 = 0.00274 moles
The volume of Ba(OH)_2 = 31.78 × 10^{-3} L
In conclusion, Molarity is
[tex]M=\frac{0.00274}{31.78 * 10^{-3} L}[/tex]
M= 0.0862 M
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