Answer
given,
borrowed money = $33000
Part of the money was borrowed at 8% be x, part at 10% be y, and part at 12% be ($33000-x-y)
x + y = 2 ($33000-x-y)
3 x + 3 y = $ 66000
x + y = $ 22000.........(1)
third part =$33000-($22000)
= $ 11000
now annual interest is
0.08 x + 0.1 y + 0.12 × 11000 = $ 3360
0.08 x + 0.1 y = 2040............(2)
0.1 x + 0.1 y = 2200..........(3)
solving equation (3) and (2)
x = $ 8000
y = $ 14000
3 rd number = $ 11000