Answer:
[tex]h=f(t)= -17.5cos(\pi /3)+20.5[/tex]
Explanation:
Amplitude is 35/2=17.5
Midline= Distance from ground + Amplitude = 17.5+3= 20.5
Period is time taken to finish 6 minutes
2π/b=T
2π/b=6
b=π/3
[tex]h=f(t)= -17.5cos(\pi /3)+20.5[/tex]
Answer:
[tex]y = 2 + \frac{35}{2}(1 - cos(\frac{\pi}{3} t))[/tex]
Explanation:
As we know that time period of the ferris wheel is given as
[tex]T = 6 min[/tex]
so we have
[tex]\omega = \frac{2\pi}{T}[/tex]
[tex]\omega = \frac{2\pi}{6} rad/min[/tex]
[tex]\omega = \frac{\pi}{3} rad/min[/tex]
now angular position at any time "t" is given as
[tex]\theta = \omega t[/tex]
so the height as a function of time is given as
[tex]y = h_i + R - Rcos\theta[/tex]
[tex]y = 2 + \frac{35}{2}(1 - cos(\frac{\pi}{3} t))[/tex]
