Answer:
[tex]\dfrac{2}{9}[/tex]
Step-by-step explanation:
There are 3 ways to have exactly two orange:
A, B orange; C blue -[tex]\dfrac{1}{6}\times \dfrac{2}{6}\times \dfrac{3}{6}[/tex]
=[tex]\dfrac{1}{36}[/tex]
A, C, orange; B blue - [tex]\dfrac{1}{6}\times \dfrac{3}{6}\times \dfrac{4}{6}[/tex]
=[tex]\dfrac{1}{18}[/tex]
B, C, orange; A blue - [tex]\dfrac{2}{6}\times \dfrac{3}{6}\times \dfrac{5}{6}[/tex]
=[tex]\dfrac{5}{36}[/tex]
The probability of exactly two of the three dice come up orange
= [tex]\dfrac{1}{36} + \dfrac{1}{18} +\dfrac{5}{36}[/tex]
=[tex]\dfrac{2}{9}[/tex]