Answer:
The difference in the mass = 7.0869 g
Explanation:
Pressure = 120 psi
The conversion of P(psi) to P(atm) is shown below:
[tex]P(psi)=\frac {1}{14.696}\times P(atm)[/tex]
So,
Pressure = 120 / 14.696 atm = 8.16552 atm
Temperature = 26 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (26 + 273.15) K = 299.15 K
Volume = 860 mL = 0.86 L (1 mL = 0.001 L)
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
8.16552 atm × 0.86 L = n × 0.0821 L.atm/K.mol × 299.15 K
⇒n = 0.2859 moles
Molar mass of air = 28.8 g/mol
Moles = Mass/Molar mass
Mass of air in the tire= Moles* Molar mass = 0.2859 moles * 28.8 g/mol = 8.2339 g
Molar mass of helium = 4.0026 g/mol
Mass of helium in the tire = 0.2859 moles * 4.0026 g/mol = 1.1443 g
The difference in the mass = 7.0869 g
