Respuesta :
Answer:
moles of carbon dioxide produced are 410.9 mol.
Explanation:
Given data:
Mass of C₆H₁₄O₂ = 16.5 g
Moles of O₂ = 499 mol
Moles of CO₂ = ?
First of all we will write the balance chemical equation.
2C₆H₁₄O₂ + 17O₂ → 14CO₂ + 12H₂O
moles of C₆H₁₄O₂ = mass × molar mass
moles of C₆H₁₄O₂ = 16.5 g × 118 g/mol
moles of C₆H₁₄O₂ = 1947 mol
Now we compare the moles of CO₂ with moles of O₂ and C₆H₁₄O₂ from balance chemical equation.
O₂ : CO₂
17 : 14
499 : 14/17× 499 = 410.9 moles
C₆H₁₄O₂ : CO₂
2 : 14
1947 : 14/2× 1947 = 13629 moles
Oxygen will be limiting reactant so moles of carbon dioxide produced are 410.9 mol.
Answer:
1.96 mole
Explanation:
Thinking process:
First, we have to write a balanced chemical equation:
[tex]C_{6}H_{14}O_{2} + 17O_{2} = 14CO_{2} + 12H_{2}O[/tex]
the mass of C6H14O2 = 16.5
the molar mass of C6H14O2 = 118.0
the number of moles of C6H14O2 = [tex]\frac{16.5}{118} \\ =0.140 mole[/tex]
the number of moles produced = 14 × number of moles of C6H14O2
= 14 × 0.140 mole
= 1.96 mole