Answer:
Mass of barium sulfate produced = 35.007 g
Explanation:
Given data:
mass of Ba(OH)₂ = 25.6 g
mass of barium sulfate = ?
Solution:
First of all we will write the balance chemical equation:
Ba(OH)₂ + H₂SO₄ → BaSO₄ + 2H₂O
Number of moles of Ba(OH)₂ = mass/molar mass
Number of moles of Ba(OH)₂ = 25.6 g / 171.34 g/mol
Number of moles of Ba(OH)₂ = 0.15 mol
Now we will compare the moles of barium sulfate with barium hydroxide.
Ba(OH)₂ : BaSO₄
1 : 1
0.15 : 0.15
Mass of Barium sulfate:
Mass = number of moles × molar mass
Mass = 0.15 mol × 233.38 g/mol
Mass = 35.007 g
