Answer:
54.1 m at [tex]-62.5^{\circ}[/tex] (south of east)
Explanation:
Displacement is a vector connecting the initial position with the final position of motion.
In this problem, the motion consists of two parts:
- A first movement 25 m east
- A second movement 48 m south
We can therefore write a vector representing the displacement as
[tex]d=(25i-48j)[/tex]
where i is the unit vector indicating the east direction and j the unit vector indicating the north direction.
Therefore, the total displacement is just the magnitude of this vector:
[tex]d=\sqrt{25^2+(-48)^2}=54.1 m[/tex]
And the direction is given by
[tex]\theta=tan^{-1}(\frac{d_y}{d_x})=tan^{-1} (\frac{-48}{25})=-62.5^{\circ}[/tex]
