Respuesta :
Answer: The mass of carbon tetrachloride required is 293.8 grams.
Explanation:
To calculate the number of moles, we use the equation:
[tex]PV=nRT[/tex]
where,
P = pressure of Freon-12 = 1.62 atm
V = Volume of Freon-12 = [tex]28.5dm^3=28.5L[/tex] (Conversion factor: [tex]1dm^3=1L[/tex] )
T = Temperature of Freon-12 = [tex]21^oC=[21+273]K=294K[/tex]
R = Gas constant = [tex]0.0821\text{ L. atm }mol^{-1}K^{-1}[/tex]
n = number of moles Freon-12 = ?
Putting values in above equation, we get:
[tex]1.62atm\times 28.5L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 294K\\n=\frac{1.62\times 28.5}{0.0821\times 294}=1.91mol[/tex]
The chemical equation for the formation of Freon-12 follows:
[tex]CCl_4+2HF\rightarrow CF_2Cl_2+2HCl[/tex]
By Stoichiometry of the reaction:
1 mole of Freon-12 is formed by 1 mole of carbon tetrachloride
So, 1.91 moles of Freon-12 will be formed by = [tex]\frac{1}{1}\times 1.91=1.91mol[/tex] of carbon tetrachloride
To calculate the mass of carbon tetrachloride, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Molar mass of carbon tetrachloride = 153.82 g/mol
Moles of carbon tetrachloride = 1.91 moles
Putting values in above equation, we get:
[tex]1.91mol=\frac{\text{Mass of carbon tetrachloride}}{153.82g/mol}\\\\\text{Mass of carbon tetrachloride}=(1.91mol\times 153.82g/mol)=293.8g[/tex]
Hence, the mass of carbon tetrachloride required is 293.8 grams.
