A student takes the elevator up to the fourth floor to see her favorite physics instructor. She stands on the floor of the elevator, which is horizontal. Both the student and the elevator are solid objects, and they both accelerate upward at 5.10 m/s2. This acceleration only occurs briefly at the beginning of the ride up. Her mass is 81.5 kg. What is the normal force exerted by the floor of the elevator on the student during her brief acceleration? (Assume the j direction is upward.)

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CarliReifsteck CarliReifsteck · Answer 1 · 2019-10-16T11:25:59+02:00

Answer:

The normal force exerted by the floor of the elevator on the student during her brief acceleration is 1214.35 N.

Explanation:

Given that,

Acceleration = 5.10 m/s²

Mass of instructor = 81.5 kg

Normal force is in upward direction and weight of the student in downward direction

So, acceleration is in upward direction

We need to calculate the normal force exerted by the floor of the elevator on the student during her brief acceleration

Using formula of force

[tex]F_{N}-mg=ma[/tex]

[tex]N_{N}=m(g+a)[/tex]

Put the value into the formula

[tex]F_{N}=81.5(9.8+5.10)[/tex]

[tex]F_{N}=1214.35\ N[/tex]

Hence, The normal force exerted by the floor of the elevator on the student during her brief acceleration is 1214.35 N.