Determine the simple interest. (Assume 360 days in a year.)
p= $544, r=0.047% per day, t= 3 months
The simple interest on $544 at 0.047% per day for 3 months is $
(Round to the nearest cent.)
.

Respuesta :

ANSWER:  

The simple interest is $23.01 approximately.

SOLUTION:

Given, p= $544, r=0.047% per day, t= 3 months  

we need to find the simple interest on $544 at 0.047% per day for 3 months.

We know that,  

[tex]Simple Interest $=\left(\frac{p \times r \times t}{100}\right)$[/tex]

where, p = principal amount

r = rate of interest

t = number of years

Here, rate and time period are in days and months respectively. But we need to convert both of them into years.

R = 0.047% [tex]\times[/tex] 360  [since we have to assume there are 360 days in a year]

R = 16.92%

Now t = 3 months

[tex]=3 \times \frac{1}{12}$ years$=\frac{1}{4}$ years[/tex]

Now, S.I = [tex]$\left(\frac{544 \times 16.92 \times \frac{1}{4}}{100}\right)$[/tex]

[tex]=\left(\frac{544 \times 4.23}{100}\right)$=\left(\frac{2301.12}{100}\right)$=23.0112$[/tex]

Hence, the simple interest is $23.01 approximately.