Answer:
The statement is always true
Step-by-step explanation:
We have,
x, x+2, x+6, x+10
There are even number of terms. So for the median we add the two middle terms and divide it by 2.
Median = (x+2+x+6)/2
= (2x+8)/2
= 2(x+4)/2
= x+4
As we know that an odd number is always odd number if we add some even number to it.
In the question, x is an odd integer so, if we add 4 then it would be again an odd integer. Therefore, the median is also an odd integer.
The statement is always true.
