Answer:
The acceleration produced is [tex]0.209 m/s^{2}[/tex]
Explanation:
By the second law of Newton, the force F is equal to:
F = ma
Where m is the mass of the object and a is the acceleration produced. So if The force gives the standard 1 kg mass an acceleration of 1.00 m/s2, that means that the force apply on A and B is equal to:
F = (1Kg) * (1.00m/s2) = 1 N
Then, if this force on A produce an acceleration of 0.530 [tex]m/s^{2}[/tex], the mass of A is:
[tex]F = m_A*a_A \\1 N = m_A* (0.530 m/s^{2} )\\\frac{1N}{0.530m/s^{2} } =m_A\\\\1.887Kg = m_A[/tex]
At the same way, if this force on B produce an acceleration of 0.344 [tex]m/s^{2}[/tex], the mass of B is:
[tex]F = m_B*a_B \\1 N = m_B* (0.344 m/s^{2} )\\\frac{1N}{0.344m/s^{2} } =m_B\\\\2.907Kg = m_B[/tex]
Therefore, if they are attached and the same force is applied, the acceleration is:
[tex]F=(m_A+m_B)*a\\1N=(1.887Kg + 2.907Kg)*a\\1N = 4.794 Kg *a\\\frac{1N}{4.794Kg}=a\\ 0.209 m/s^{2} =a[/tex]
