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A 500-g squirrel with a surface area of 1020 square centimeters falls from a 5.5-meter tall tree to the ground. What is its terminal velocity? (Use the drag coefficient of a horizontal skydiver, and assume that the density of the air is 1.16 kg/m33).

Respuesta :

Answer:

Terminal velocity will be 9.10 m/sec

Explanation:

We have given mass of squirrel m = 500 gram = 0.5 kg

Area [tex]A=1020cm^2=0.1020m^2[/tex]

Density is given as [tex]\rho =1.16kg/m^3[/tex]

We have to find the terminal velocity

Terminal velocity is given by [tex]v=\sqrt{\frac{2mg}{\rho CA}}[/tex], here m is mass, g is acceleration due to gravity , C is drag coefficient,  [tex]\rho[/tex] is density

Here value of drag coefficient C = 1

So terminal velocity [tex]v=\sqrt{\frac{2\times 0.500\times 9.81}{1.16\times 1\times 0.1020}}=9.10m/sec[/tex]