Answer:
W = 85.73 m
Explanation:
given,
surveyor walks = 118 m
makes an angle of = 36.0° with the tree
to find the width of the river
[tex]tan \theta = \dfrac{W}{distance}[/tex]
[tex]tan 36^0 = \dfrac{W}{118}[/tex]
[tex]tan 36^0 = \dfrac{W}{118}[/tex]
[tex]W = 118 \times 0.7265[/tex]
W = 85.73 m
hence, the width of the river is equal to W = 85.73 m