Answer:Pan will move up together with the lid.
Explanation:
Given
diameter of pot(d)=30 cm
Temperature of room[tex]=20^{\circ}\approx 293 K[/tex]
assume vapor pressure of water at 293 K is [tex]P_v=2.3 kPa, P_{atm}=101.32 kPa[/tex]
mass of food and the pot=8 kg
Pressure Difference [tex]\Delta P=P_{atm}-P_{v}=101.3-2.3=99 kPa[/tex]
Area of lid [tex]A=\frac{\pi d^2}{4}=0.0706 m^2[/tex]
Force due to Pressure difference [tex]=\Delta P\times A[/tex]
[tex]=99\times 10^3\times 0.0706=6998.805 N[/tex]
Downward Force opposing it will be weight=mg
[tex]W=8\times 9.8=78.4 N[/tex]
Downward force is less than force due to pressure difference thus Pan will move up together with the lid
