Answer:
The minimum acceleration will be [tex]11.40m/sec^2[/tex]
Explanation:
We have given that coefficient of static friction [tex]\mu _s=0.860[/tex]
Frictional force is given by [tex]F=\mu_s N=\mu _sma[/tex]
Weight is given by [tex]W=mg[/tex]
For train to allow the bat to remain in place [tex]mg=\mu _sma[/tex]
[tex]a=\frac{g}{\mu _s}=\frac{9.81}{0.860}=11.40m/sec^2[/tex]
So the minimum acceleration will be [tex]11.40m/sec^2[/tex]
