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A 86.6-kg man is standing on a frictionless ice surface when he throws a 2.40-kg book horizontally at a speed of 10.9 m/s. With what speed does the man move across the ice as a result? Give your answer in m/s, and be sure to use three significant figures in your answer.

Respuesta :

krlosdark12

Answer:

The speed of the man is 0.302m/s in the opposite direction.

Explanation:

We need to apply the theorem of linear momentum:

[tex]m1*vo1+m2*vo2=m1*vf1+m2*vf2[/tex]

The instant before the man throws the book the velocity is zero:

[tex]86.6kg*(0)+2.40kg(0)=86.6kg*vf1+2.40kg*(10.9m/s)\\\\vf1=\frac{-2.40kg*(10.9m/s)}{86.6kg}\\vf1=-0.302m/s[/tex]

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