Respuesta :
Answer:
a). 87.5 mA or [tex]87.5 x10^{-3}[/tex]A
b). 1.78 [tex]\frac{m}{s}[/tex]
Explanation:
[tex]d=2.6 mm \\Q=420C\\t=80min\\n=5.8x10^{28} \\q=1.6x10^{-19}[/tex]
n the number of free electrons is 28 in text reference and if they don't give q is take as the charge of electron.
a).
[tex]I=\frac{Q}{t}\\ I= \frac{420 C}{80 min}*\frac{1min}{60 s} =\frac{420 C}{4800s}\\ I=87.5 x10^{-3}[/tex]A
b).
[tex]I=n*abs (q)*V_{d}*A[/tex]
[tex]A= \pi * (\frac{d}{2})^{2} \\A=\pi (*\frac{2.6x10^{-3} m}{2})^{2} \\A=5.309x10^{-6}[/tex]
[tex]V_{d} =\frac{I}{n*abs(q)*A} \\V_{d}=\frac{87.5 x10^{-2} }{5.8x^10{28} *1.6x^{-19} *5.3x^{6} }\\V_{d}=1.78 \frac{m}{s}[/tex]
The current flow is the flow of electron inside the particle or wire.
- The current in the wire is [tex]87.5\times10^{-19}[/tex] ampere.
- The magnitude of the drift velocity of the electron in the wire is 1.78 m per sec
What is current flow in a particle?
The current flow is the flow of electron inside the particle or wire. It can be given as,
[tex]I=nq(vA)[/tex]
Here [tex]n[/tex] is the number of electron, [tex]q[/tex] is the charge of the particle [tex]v[/tex] is the drift velocity of electron and [tex]A[/tex] is the area.
Given information-
The diameter of the silver wire is 2.6 mm.
The charge of the wire is 420 C in 80 min or 4800 seconds.
- (a) The current in the wire-
Current is the charge per unit time. thus,
[tex]I=\dfrac{420}{4800} \\I=87.5\times10^{-19}[/tex]
Thus the current in the silver wire is [tex]87.5\times10^{-19}[/tex] ampere.
- (b) The magnitude of the drift velocity of the electrons in the wire-
The area of the given wire is,
[tex]A=\pi\times\dfrac{0.0026^2}{4} \\A=5.309\times10^{-6}[/tex]
And the number of free electron in silver is 28(let). then,
[tex]n=5.8\times10^{28}[/tex]
Hence, use the above formula in order to find the velocity of the electron as,
[tex]v=\dfrac{87.5\times10^{-2}}{5.8\times10^{28}\times1.6\times10^{-19}\times5.3\times10^{6}}\\v=1.78\rm m/s[/tex]
Hence,
- The current in the wire is [tex]87.5\times10^{-19}[/tex] ampere.
- The magnitude of the drift velocity of the electron in the wire is 1.78 m per sec.
Learn more about the electric current here;
https://brainly.com/question/1100341
