Answer:0.38
Step-by-step explanation:
Let total Students be x
then 20% is overweight(A)
20 % exercise regularly(B)
2 % are overweight and exercise regularly
Probability that a randomly selected is either overweight or exercises regularly or both
i.e. [tex]P\left ( A\cup B \right )=P\left ( A \right )+P\left ( B\right )-P\left ( A\cap B\right )[/tex]
[tex]P\left ( A\cup B \right )=0.2+0.2-0.02=0.38[/tex]