Answer:
The molar mass of M is 44.06 g/mol
Explanation:
The reaction between a metal chloride and silver nitrate will be given by the balanced equation:
MCl(aq)+ AgNO₃(aq) →MNO₃(aq) + AgCl(s)
We are required to calculate the molar mass of M
We are going to use the following steps:
Step 1: Number of moles of silver nitrate
Number of moles = Mass of a compound ÷ Molar mass of the compound
Molar mass of silver nitrate is 169.87 g/mol
Therefore;
Number of Moles = 3.48 g ÷ 169.87 g/mol
= 0.0205 moles
Step 2: Moles of MCl that reacted
From the equation; 1 mole of MCl reacts with 1 mole of silver nitrate
Therefore; the mole ratio of MCl : AgNO3 is 1: 1
Thus;
Moles of MCl = 0.0205 moles
Step 3: Molar mass of MCl
From the question 1.63 g sample of MCl was used
Therefore;
1.63 g = 0.0205 moles
Molar mass is the relative formula mass of one mole of a compound
Therefore;
Molar mass = 1.63 g ÷ 0.0205 moles
= 79.51 g/mol
Step 3: Molar mass of M
The relative formula mass of MCl is 79.51 g/mol
Atomic mass of Cl = 35.45
Thus;
79.51 g/mol = M + 35.45 g
M = 79.51 - 35.45
= 44.06
Thus, the molar mass of M is 44.06 g/mol
