Answer:
0.183 N/s
Step-by-step explanation:
Given
mass of object[tex]=51 gm[/tex]
acceleration [tex]a\left ( \frac{\mathrm{d} v}{\mathrm{d} t}\right )=9 m/s^2[/tex]
[tex]\frac{\mathrm{d} m}{\mathrm{d} t}=9 gm/s[/tex]
Force on a object is given by
[tex]F\left ( t\right )=m\left ( t\right )a\left ( t\right )[/tex]
Change in force is given by
[tex]\frac{\mathrm{d} F\left ( t\right )}{\mathrm{d} t}=\frac{\mathrm{d} m}{\mathrm{d} t}a\left ( t\right )+m\left ( t\right )\frac{\mathrm{d} a\left ( t\right )}{\mathrm{d} t}[/tex]
[tex]\frac{\mathrm{d} F\left ( t\right )}{\mathrm{d} t}=9\times 10^{-3}\times 9+2\times 51\times 10^{-3}[/tex]
[tex]=183\times 10^{-3}=0.183 N/s[/tex]
