Answer:
[tex]V={3.5\times 10^{5}}\ m/s[/tex]
Explanation:
Given that
VA - VB = 36.0 V
If we assume that ,the particle is electron.
For electron
The mass of electron
[tex]m=9.1\times 10^{-31}\ kg[/tex]
The charge on electron
[tex]q=1.6\times 10^{-19}\ C[/tex]
q( VA - VB) = 1/2 m V² (energy conservation)
[tex]1.6\times 10^{-19}\times 36=\dfrac{1}{2}\times 9.1\times 10^{-31}V^2[/tex]
[tex]\dfrac{3.2\times 10^{-19}\times 36}{9.1\times 10^{-31}}\ = V^2[/tex]
[tex]V=\sqrt{1.265\times 10^{13}}\ m/s[/tex]
[tex]V={3.5\times 10^{5}}\ m/s[/tex]
