Answer:
a) t= 0.515 s
b) vf= 5.047 m/s
Explanation:
Because ball move with uniformly accelerated movement we apply the following formulas:
d= v₀t+ (1/2)*g*t² Formula (1)
vf= v₀+gt Formula (2)
Where:
d:displacement in meters (m)
t : time in seconds (s)
v₀: initial speed in m/s
vf: final speed in m/s
g: acceleration due to gravity in m/s²
Known data
v₀=0
d= 1.30 m
g= 9.8 m/s²
Problem development
a) We appy the formula 1 to calculate the time (t):
d= v₀t+ (1/2)*g*t²
1.30= 0+ (1/2)* (9.8)*t²
1.30=4.9*t²
t²=1.30/4.9
[tex]t=\sqrt{\frac{1.3}{4.9} }[/tex]
t= 0.515 s
b) We appy the formula 2 to calculate the final speed (vf):
vf= v₀+gt
vf= 0+(9.8)*(0.515)
vf= 5.047 m/s
