QueasyUnicorn14
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Need Help ASAP!!


A stadium has 53,000 seats. Seats sell for ​$28 in Section​ A, ​$16 in Section​ B, and ​$12 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in ​$1,118,800 from each​ sold-out event. How many seats does each section​ hold?

Respuesta :

sqdancefan

Answer:

  • A: 26,500
  • B: 14,700
  • C: 11,800

Step-by-step explanation:

Section A comprises half the seats, so contains 26,500 seats.

The revenue from those is ...

  $28×26,500 = $742,000

so the revenue from the remaining seats is ...

  $1,118,800 -742,000 = $376,800

An equation for that can be written using "b" for the number of section B seats:

  16b +12(26,500 -b) = 376,800

  4b + 318,000 = 376,800

  b = (376,800 -318,000)/4 = 14,700

Then the remaining number of seats is the number in section C:

  26,500 -14,700 = 11,800

There are 26,500 seats in Section A, 14,700 seats in Section B, and 11,800 seats in Section C.

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