For this case, we propose a rule of three for each amount. Then we will add 20% and see if it is less than or equal to $60, if that is true then Clay can pay the tip of 20%:
$ 48.53 ------------> 100%
x ----------------------> 20%
Where "x" represents the amount corresponding to 20%.
[tex]x = \frac {20 * 48.53} {100}\\x = 11.6472[/tex]
So, we have:
[tex]48.53 + 11.6472 =\\60.1772[/tex]
With this bill Clay could not leave a 20% tip.
$ 49.75 ------------> 100%
x ----------------------> 20%
Where "x" represents the amount corresponding to 20%.
[tex]x = \frac {20 * 49.75} {100}\\x = 9.95[/tex]
So, we have:
[tex]49.75 + 9.95 =\\59.7 <60[/tex]
With this bill Clay could leave a 20% tip.
$ 54.99 ------------> 100%
x ----------------------> 20%
Where "x" represents the amount corresponding to 20%.
[tex]x = \frac {20 * 54.99} {100}\\x = 10,998[/tex]
So, we have:
[tex]54.99 + 10.998 =\\65.988[/tex]
With this bill Clay could not leave a 20% tip.
$ 61.60 ------------> 100%
x ----------------------> 20%
Where "x" represents the amount corresponding to 20%.
[tex]x = \frac {20 * 61.60} {100}\\x = 12.32[/tex]
So, we have:
[tex]61.60 + 12.32 =\\73.92[/tex]
With this bill Clay could not leave a 20% tip.
$ 58.80 ------------> 100%
x ----------------------> 20%
Where "x" represents the amount corresponding to 20%.
[tex]x = \frac {58.80 * 20} {100}\\x = 11.76[/tex]
So, we have:
[tex]58.80 + 11.76 = 70.56[/tex]
With this bill Clay could not leave a 20% tip.
$ 50 ------------> 100%
x ----------------------> 20%
Where "x" represents the amount corresponding to 20%.
[tex]x = \frac {50 * 20} {100}\\x = 10[/tex]
So, we have:
[tex]50 + 10 = 60[/tex]
With this bill Clay could leave a 20% tip.
So, I could only tip with the options B y F
ANswer:
Option B y F
Answer: to go about this we need to test each bill to see which one will 20% of will add up to $60
Step-by-step explanation: from the list of bills 20% $50 will add up to give $60
I. E 20/100*50=0.2*100=$10
$50+$10=$60
