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If 32.146g of MgSO4 is added to enough water to make 100.00mL solution, what is the molarity of MgSOA?1) 2.6706 M 2) 3.7445M 3) 0.037445 4) 0.0026706 M 5) 3869.4 M

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Answer:

[tex]M=2.6706M[/tex]

Explanation:

Hello,

At first, the moles of magnesium sulfate must be computed by knowing that its molecular mass has a value of  120.366 g/mol:

[tex]n_{MgSO_4}=32.146gMgSO_4*\frac{1mol MgSO_4}{120.366gMgSO_4} =0.26706mol MgSO_4[/tex]

Now, by knowing that the volume must be in L, it turns out into 0.10000 L, thus:

[tex]M=\frac{0.26706mol MgSO_4}{0.10000L}\\ M=2.6706M[/tex]

Best regards.

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