Respuesta :
Answer:
force at the top will be 388 N which is nearly equal to 389
option (b) is correct
Explanation:
We have given velocity of the moving car v = 10 m/sec
Radius of the circular section r = 30 m
Mass of the passenger m = 60 kg
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
At the top normal force is given by [tex]noraml\ force=mg-\frac{mv^2}{r}[/tex]
So force at top will be [tex]F=60\times 9.8-\frac{60\times 10^2}{30}=388N[/tex]
So force at the top will be 388 N which is nearly equal to 389
So option (b) is correct
Answer:
option B
Explanation:
given.
car is moving at = 10 m/s
bump of radius = 30 m
normal force = ?
mass of the passenger = 60 kg
m × g = 60 × 9.81 N
normal force acting
=[tex]mg - \dfrac{mv^2}{R}[/tex]
=[tex]60\times 9.81 - \dfrac{60\times 10^2}{30}[/tex]
=388.6 N
the normal force acting is equal to 389 N
hence, the correct answer is option B
