Answer: [tex]7.77(10)^{-13} V[/tex]
Explanation:
The capacitance [tex]C[/tex] is defined as the relationship between the electric charge of each conductor and the potential difference between them. That is, it is the capacity of a device to store electrical charge.
Mathematically it is defined as:
[tex]C=\frac{Q}{V}[/tex]
Where:
[tex]C=3.50 pF=3.50(10)^{-12} F[/tex] is the capacitance value of a capacitor.
[tex]Q=4.50 C[/tex] is the electric charge of the conductor
[tex]V[/tex] is the electric potential to which the conductor is located, measured in Volt.
Isolating [tex]V[/tex]:
[tex]V=\frac{Q}{C}[/tex]
[tex]V=\frac{4.50 C}{3.50(10)^{-12} F}[/tex]
Finally:
[tex]V=7.77(10)^{-13} V[/tex]
