Answer:
Capacitance of the capacitor is c= 0.29 F
Explanation:
Energy the capacitor store related in the equation
[tex]E= 12[/tex]Joules
[tex]v= 9 [/tex]volts
[tex]E=\frac{1}{2} *C*V^{2}\\ C=\frac{E*2}{V^{2} } \\ C=\frac{12 J*2}{9 volts^{2} } \\[/tex]
[tex]C= \frac{24 J}{81} = 0.296 \\C=0.296[/tex]F
The capacitance of the capacitor for a voltage of 9 V
