Respuesta :
Answer: 0.11 g/ml
Explanation:
Half-life = 81 minutes
First we have to calculate the rate constant, we use the formula :
[tex]k=\frac{0.693}{81\text{minutes}}[/tex]
[tex]k=0.008\text{minutes}^{-1}[/tex]
Now we have to calculate the age of the sample:
Expression for rate law for first order kinetics is given by:
[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]
where,
k = rate constant = 0.008\text{minutes}^{-1}[/tex]
t = time of decomposition = 324 minutes
a = let initial concentration of the reactant = 1.8 g/ml
a - x = concentration after decay process = ?
Now put all the given values in above equation, we get
[tex]324=\frac{2.303}{0.008}\log\frac{1.8}{a-x}[/tex]
[tex](a-x)=0.11g/ml[/tex]
Thus concentration after 324 minutes will be 0.11 g/ml.
