Answer:
Distance traveled will be 5.6307 m
Explanation:
Time t = 3 sec
We have given force F = 25 N
We know that force is given by F = ma
So ma = 25 -----------eqn 1
Weight is given by W = 196 N
We know that weight is given by W = mg
So mg = 196 -----------------eqn 2
From equation 1 and equation 2 [tex]\frac{a}{g}=\frac{25}{196}[/tex]
[tex]a=1.2512m/sec^2[/tex]
Initial velocity is given as 0 so u = 0 m/sec
From second equation of motion [tex]s=ut+\frac{1}{2}at^2=0\times 3+\frac{1}{2}\times 1.2512\times 3^2=5.6307m[/tex]
