Answer:
13.32 m/s
39.96 m
79.96 m
59.98 m
Explanation:
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow 40=0\times 6+\frac{1}{2}\times a\times 6^2\\\Rightarrow a=\frac{40\times 2}{6^2}\\\Rightarrow a=2.22\ m/s^2[/tex]
[tex]v=u+at\\\Rightarrow v=0+2.22\times 6\\\Rightarrow v=13.32\ m/s[/tex]
Maximum speed of Sergio is 13.32 m/s
If Sergio runs for 3 seconds after reaching his maximum speed
Distance = Speed × Time
[tex]\text{Distance}=13.32\times 3=39.96\ m[/tex]
In the three second Sergio will cover 39.96 m
In 6 seconds he covers 40 m. In the extra 3 seconds he covers 39.96 m
So, total distance covered in 9 seconds is 40+39.96 = 79.96 m
Distance covered in 6 seconds is 40 m.
[tex]\text{Distance}=13.32\times (7.5-6)=19.98\ m[/tex]
In 1.5 seconds he will cover 19.98 m
So, in 7.5 seconds he will cover 40+19.98 = 59.98 m
