Answer:
3; Double Displacement
Explanation:
Balancing is making the number of atoms of each element same on both the sides (reactant and product side).
To find the number of atoms of each element we multiply coefficient and the subscript
For example [tex]5Ca_1Cl_2[/tex] contains
5 × 1 = 5 ,Ca atoms and
5 × 2 = 10, Cl atoms
If there is a bracket in the chemical formula
For example [tex]3Ca_3 (P_1 O_4 )_2[/tex] we multiply coefficient × subscript × number outside the bracket to find the number of atoms
(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )
So
3 × 3 = 9 , Ca atoms
3 × 1 × 2 = 6, P atoms
3 × 4 × 2 = 24, O atoms are present
Let us balance the equation given
[tex]Ca_3 N_2+6H_2 0>Ca(OH)_2+2NH_3[/tex]
(UNBALANCED)
Reactant side Number of atoms or groups Product side
of each element
3 Ca 1
2 N 2
12 H 8
6 O 2
Multiplying [tex]Ca(OH)_2[/tex] on the right side by 3, we will have
[tex]Ca_3 N_2+6H_2 0>3Ca(OH)_2+2NH_3[/tex]
Reactant side Number of atoms or groups Product side
of each element
3 Ca 3
2 N 2
12 H 12
6 O 6
Balanced!!!!
