The conversion of cyclopropane to propene in the gas phase is a first-order reaction with a rate constant of 6.7 x 10-4 s -1 at 500 C. Cyclopropane (CH2CH2CH2) -- CH3-CH=CH2 (propene) If the initial concentration of the reactant was 0.25 M, what is the concentration after 8.8 min?

Question

contestada

Respuesta :

sebassandin sebassandin · Answer 1 · 2019-10-27T15:27:30+01:00

Answer:

[tex]C_f=0.1755M[/tex]

Explanation:

Hello,

Based on the information and the units of the given data, the integrated rate law turns out into:

[tex]\frac{dC}{dt}=-kC\\ C_f=C_0exp(-kt)\\C_f=0.25M*exp(-6.7x10^{-4}s^{-1}*8.8min*\frac{60s}{1min} )\\C_f=0.1755M[/tex]

Best regards.

Answer Link

abhishekprakash2625 abhishekprakash2625 · Answer 2 · 2022-02-16T18:08:06+01:00

The study of genes and inheritance is called genetics. There are different types of genes and these are recessive and dominant.

The correct answer is cf is 0.1755

Hydrocarbon, any of a class of organic chemical compounds composed only of the elements carbon and hydrogen.

According to the question,

[tex]\frac{dC}{dt}= -kC[/tex]

[tex]C_f = C_oexp(-kt)\\C_f=0.25M*exp(-67*10^{-4}*8.8*60)\\C_f=0.1755[/tex]

Hence, the correct answer is 0.1755.

For more information about the hydrocarbon, refer to the link:-

https://brainly.com/question/7932885