Respuesta :
Let's write the inequality down:
[tex]y > -\dfrac{1}{2}x+7[/tex]
Let's plug the values x=6, y=4:
[tex]4 > -\dfrac{1}{2}\cdot 6+7 \iff 4 > -3+7 \iff 4>4[/tex]
Which is false, unless you meant "greater than or equal to". In that case, the pair is a solution.
Answer:
No, the ordered pair(6,4) is not a solution to y > (-1/2)x + 7.
Step-by-step explanation:
First lets establish the area of the solutions of y > (-1/2)x +7. Because it is y>, this means that the area of the solutions is anything above the y value not including the y value itself. So, if we plug in x=6 into the equation, we will get y=4, yet because it is not greater than the y-value itself(4>4 is not true), (6,4) is not a solution to the equation. If it was y is greater than or equal to, the story would be different and (6,4) would be a solution since it includes the y-value itself.
