Explanation:
S =ut + 1/2at^2
S = 0×6.5 + (1/2 × 9.54) × 6.5^2
S =0 + 4.77 ×42.25
S=201.5m
The distance covered by the car 403.06 meters
The calculation is done as follows
initial velocity(u)= 0
acceleration= 9.54 m/s²
time= 6.5 seconds
S= ut + 1/2at²
= (0)(6.5) + 1/2(9.54)(6.5²)
=0 + 0.5(9.54)(42.25)
= 403.06 meters
Hence the distance covered by the car is 403.06 meters
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