Answer:
Slope of a line perpendicular to the line y=8x+1 is [tex]\frac{-1}{8}[/tex]
Solution:
Given y=8x+1
The slope - intercept form equation of line is given as
y = mx + c --- eqn 1
Where m is the slope of the line.
The coefficient of “x” is the value of slope of the line.
"c" is the y – intercept which is the value of y at the point where the line crosses the y-axis
From question, given that y = 8x + 1
Comparing the given equation y=8x+1 with equation 1, we get
m = 8 and c = 1
The equation of a perpendicular line to y=8x+1 must have a slope that is the negative reciprocal of the original slope.
[tex]\mathrm{m}_{\text {reciprocal }}=-\frac{1}{8}[/tex]
Hence the slope of the line perpendicular to the line y=8x+1 is [tex]\frac{-1}{8}[/tex]
