Respuesta :
Answer:
[tex]2x^3-6x^2-x[/tex]
Step-by-step explanation:
[tex]\frac{f(x)}{g(x)}=\frac{16x^5-48x^4-8x^3}{8x^2}[/tex]
[tex]\frac{f(x)}{g(x)}=\frac{16x^5}{8x^2}-\frac{48x^4}{8x^2}-\frac{8x^3}{8x^2}[/tex]
[tex]\frac{f(x)}{g(x)}=\frac{16}{8}x^{5-2}-\frac{48}{8}x^{4-2}-\frac{8}{8}x^{3-2}[/tex]
[tex]\frac{f(x)}{g(x)}=2x^{3}-6x^2-1x^1[/tex]
[tex]\frac{f(x)}{g(x)}=2x^3-6x^2-x[/tex]
Answer:
First, we have to express the fraction between these two functions:
[tex]\frac{f(x)}{g(x)}=\frac{16x^{5}-48x^{4}-8x^{3}}{8x^{2} }[/tex]
Then, we separate the denominator to operate each term in the numerator:
[tex]\frac{16x^{5}}{8x^{2}}-\frac{48x^{4}}{8x^{2}}-\frac{8x^{3}}{8x^{2}}[/tex]
Now, we have to divide numbers and terms, remember that power dividing requires to subtract exponents and maintain the same base:
[tex]2x^{3}-6x^{2}-x[/tex]
Therefore, the result of this function division is:
[tex]2x^{3}-6x^{2}-x[/tex]
