Hydrogen gas and nitrogen gas can react to form ammonia according to this equation:

N2(g)+3H2(g)→2NH3(g)

How many liters of nitrogen gas are required to produce 2 moles of NH3(g)?

One mole of gas occupies 22.4 liters under standard conditions of temperature and pressure (STP) .

A. 11.2 L

B. 22.4 L

C. 44.8 L

D. 67.2 L

I think its either D or A. Please correct me if i am wrong. Thank you.

The balanced chemical equation has been the representation of the stoichiometric coefficient for the determination of moles of reactants and products involved.

Computation for Volume of nitrogen gas

According to the balanced chemical equation, for the production of 2 moles of ammonia, 1 mole of nitrogen and 1 mole of hydrogen gas reacted.

Thus, the moles of nitrogen gas required for 2 moles of ammonia has been 1 mole.

It has been known that at STP, the volume of 1 mole of gas has been 22.4 L.

Thus, the volume of nitrogen gas required for the production of 2 moles ammonia has been 22.4 L. Thus, option B is correct.

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