contestada

Ball A is attached to one end of a rigid massless rod, while an identical ball B is attached to the center of the rod, as shown in the figure. Each ball has a mass of m =
0.450 kg, and the length of each half of the rod is L = 0.420 m. This arrangement is held by the empty end and is whirled around in a horizontal circle at a constant rate,
so that each ball is in uniform circular motion, Ball A travels at a constant speed of VA = 5.10 m/s. Find (a) the tension of the part between A and B of the rod and (b)
the tension of the part between B and the empty end.

Respuesta :

Hania12

Answer:

Explanation:

From the given data angular speed is equal to

                    w=VA/RA

                     w=5.1/2*0.42

                        =6.07 rad/s

      a)               TAB=m*a

                             =m*(RA)*([tex]w^{2}[/tex])

                              =0.45*(2*0.42)([tex]6.07^{2}[/tex]

                              =13.92 N

     b)                 TBO=TAB+m*a

                                  =13.92+0.45*0.42*[tex]6.07^{2}[/tex]

                                  =20.88 N