Answer:
Option A = 1 L
Explanation:
Given data:
Volume of CH₄ = 2 L
Volume of O₂ = 2 L
Volume of CO₂ = ?
Solution:
First of all we will write balance chemical equation.
CH₄ + 2O₂ → 2H₂O + CO₂
Number of moles of CH₄:
PV = nRT
n = PV/RT
n = 1 atm. 2 L / 0.0821 atm. L. mol⁻¹ . K⁻¹ × 273.15 k⁻¹
n = 2 atm . L / 22.43 atm. L. mol⁻¹
n = 0.09 mol
Number of moles of O₂:
PV = nRT
n = PV/RT
n = 1 atm. 2 L / 0.0821 atm. L. mol⁻¹ . K⁻¹ × 273.15 k⁻¹
n = 2 atm . L / 22.43 atm. L. mol⁻¹
n = 0.09 mol
Now we compare the moles of O₂ and CH₄ with CO₂ from balance chemical equation
CH₄ : CO₂
1 : 1
0.09 : 0.09
O₂ : CO₂
2 : 1
0.09 : 1/2×0.09 = 0.045 mol
Volume of CO₂
PV = nRT
V = nRT / P
V = 0.045 mol × 0.0821 atm. L. mol⁻¹ . K⁻¹ × 273.15 k⁻¹ / 1 atm
V = 1.0092 L
Which is approximately equal to 1 L.
