How many gallons of pure water should be added to 10 gallons of a solution containing 15 % juice so that the remaining solution contains 5 % juice? Fill in the table: What is the amount of juice in the original solution? a=. What is the original amount of solution in gallons? b =. How much juice is added? c= . How much total solution is added? d=.

a. The amount of juice in the original solution is 1.5 gallons. b. Original amount of solution is 10 gallons c. No juice is added d. 20 gallons solution (pure water) is added.

What are Percentages?

A percentage is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25 which is equal to 25%.

The concentration of the original solution is 15%, while the quantity is 10 gallons. So, the amount of juice in the original solution is,

The Amount of juice in original solution = 15% of 10 gallons

= 0.15 × 10 gallons

= 1.5 gallons

Now, Consider the amount of water mixed be x gallons in the original solution, then we can write as;

5% of the mixed solution = 1.5 gallons

Mixed Solution = 1.5 /0.05

Mixed solution = 30 gallons

Thus, the volume of the mixed solution is 30 gallons, while the volume of the original solution was 10 gallons.

Hence, 20 gallons of water are needed to be mixed into the original solution. The amount of juice in the original solution is 1.5 gallons.

Learn more about Percentages:

brainly.com/question/6972121

#SPJ2