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The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y – 4 = 1/4 (x – 8). What is the slope-intercept form of the equation for this line?

y = y = 1/4x - 12.x – 12
y = y = 1/4x - 4.x – 4
y = y = 1/4x + 2.x + 2
y = y = 1/4x + 6.x + 6

Respuesta :

gmany

Answer:

[tex]\large\boxed{y=\dfrac{1}{4}x+2}[/tex]

Step-by-step explanation:

The slope-intercept form of an equation of a line:

[tex]y=mx+b[/tex]

m - slope

b - y-intercept

We have the equation in the point-slope form.

[tex]y-4=\dfrac{1}{4}(x-8)[/tex]

Convert to the slope-intercept form:

[tex]y-4=\dfrac{1}{4}(x-8)[/tex]    multiply both sides by 4

[tex]4y-16=x-8[/tex]           add 16 to both sides

[tex]4y=x+8[/tex]             divide both sides by 4

[tex]y=\dfrac{1}{4}x+2[/tex]

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