Write an equation of the line passing through the point (-10,3) that is parallel to the line 5x+2y=12. (In y=mx+b form)
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Answer:
The answer to your question is: y = -5/2 x - 22
Step-by-step explanation:
Data
A ( -10, 3)
Parallel to 5x + 2y = 12
Process find slope (m)
5x + 2y = 12
2y = -5x + 12
y = (-5/2) x + 12/2
y = (-5/2) x + 6
slope = m = -5/2
(y - y1) = m(x - x1)
( y - 3) = -5/2 ( x + 10)
y - 3 = -5/2 x - 50/2
y = -5/2 x - 25 + 3
y = -5/2 x - 22
Two lines are parallel if they never meet, and we can say that two lines will be parallel if and only if they have the same slope and different y-intercept.
We will find that the solution here is y = -2.5*x + 28
Let's see how to get that solution:
First, we can write our line as a general line, like:
y = a*x + b
Where a is the slope and b is the y-intercept.
Now we want this line to be parallel to:
5x + 2y = 12
First, let's rewrite the above line in slope-intercept form, to do that, we need to isolate y in one side of the equation.
2y = 12 - 5x
y = 12/2 -(5/2)*x
y = 6 - 2.5*x
Now we know the slope of this line, and remember, the parallel line will have this same slope, then our line will be:
y = -2.5*x + b
To find the value of b, we can use the fact that this line passes through the point (-10, 3). This means that when x = -10, we have y = 3
Replacing these in the line equation we get:
3 = -2.5*10 + b
3 = -25 + b
3 + 25 = b
28 = b
Then the equation of the line is:
y = -2.5*x + 28
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