Answer:
Area swept by minute hand of 14 cm in 5 minutes = 51.33
[tex]\mathrm{cm}^{2}[/tex]
Solution:
Given that length of the minute hand = 14 cm
Need to calculate the area swept by minute hand in 5 minutes.
As in 1 hour , that is 60 minutes , minute hand completes a circle .
So area swept by minute hand of 14 cm in 60 minutes = area of circle of radius 14 cm
As area of circle = [tex]\pi r^{2}[/tex]
where r is radius
So area swept by given minute hand in 60 minutes = [tex]\pi \times 14^{2}=\frac{22}{7} \times 14 \times 14=616[/tex]
So area swept by given minute hand in 1 minute = [tex]\frac{616}{60}[/tex]
And area swept by given minute hand in 5 minute = [tex]\frac{616}{60} \times 5=51.33[/tex]
Hence area swept by minute hand of 14 cm in 5 minutes is 51.33
[tex]\mathrm{cm}^{2}[/tex]
