For this case we can translate the given statement as:
Isopropyl alcohol vapors have been sampled using an activated carbon tube for 8 hours at a flow of 20 ml/min: what was the volume of the sampled air?
By definition, the volumetric flow rate is given by:
[tex]Q = \frac {V} {t}[/tex]
Where:
V: It's the volume
t: It's time
Then, the volume is given by:[tex]V = Q * t[/tex]
According to the problem data we have:
[tex]Q = 20 \frac {ml} {min}\\t = 8h * \frac {60} {1} \frac {min} {h} = 480min[/tex]
Substituting the values we have:
[tex]V = 20 \frac {ml} {min} * 480min\\V = 9600ml[/tex]
Finally, the volume of the sample is:
9600ml
Answer:
9600ml
