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What is the equation of the line that is parallel to the line y-1 = 4(x + 3) and passes through the point (4, 32)?
A y=-1÷4x+33
B y= -1÷4x + 36
C y=4x-16
D y = 4x + 16
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Respuesta :

Answer:

slope of the line:  m=4

point (4, 32)

(y-32)= 4(x-4)

y-32 = 4x-16

y= 4x-16 +32

y=4x +16

Answer: D

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