Answer:
a) u = 31.197 m/s
b) [tex]h_{max} = 49.47 m[/tex]
Explanation:
given,
weight = 3 N
mass = 3/ 9.81 = 0.305 kg
h = 15.9 m
velocity at which it is traveling upward = 25.7 m/s
a) using work energy principle
[tex]work = K.E_f - K.E_I[/tex]
[tex]mgh = \dfrac{1}{2}mv_f^2-\dfrac{1}{2}mv_i^2[/tex]
[tex]-3 \times 15.9 =\dfrac{1}{2}\times 0.305 \times 25.7^2-\dfrac{1}{2}0.305\timesv_i^2[/tex]
u = 31.197 m/s
b) At maximum height
[tex]-mgh_{max}= \dfrac{1}{2}mv_f^2-\dfrac{1}{2}mv_i^2[/tex]
[tex]-3\times h_{max}= \dfrac{1}{2}m0^2-\dfrac{1}{2}0.305\times 31.197^2[/tex]
[tex]h_{max} = 49.47 m[/tex]
